If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+3x-230=0
a = 4; b = 3; c = -230;
Δ = b2-4ac
Δ = 32-4·4·(-230)
Δ = 3689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3689}}{2*4}=\frac{-3-\sqrt{3689}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3689}}{2*4}=\frac{-3+\sqrt{3689}}{8} $
| 1x+1x*1.5=850 | | 14x+90=12x-50 | | 1x+1x×1.5=850 | | k–3.5=21 | | 6(h+4)=-2h+6 | | 4x(4x-14)=0 | | 98.1=9(m+3.6) | | 1z-7/5=-3 | | 6w-10=3w+20 | | −4p+37=13 | | 14x2+12=-29x | | 18x+12=10x | | 10-3r=27 | | n*0.1=9 | | 6y-3y-13=49.19 | | 3g^2+6g–72=0 | | 2x(x+20)x=180 | | -0.75p-2=-2.75p | | 1r=3r+30 | | -0.75p-2=-2.75 | | -f-80=11 | | z^2–15z+14=0 | | 3.5+p/7=-52 | | -21=-2c-15-2c+7 | | z2–25=0 | | 10x-5=6x+5 | | 2x+3=1000 | | X+5=19-3x | | 3 / 1 + 9 - y = 0 | | -75=-25x | | 29y^2-36y=0 | | 3x+7=6x-6 |